To improve network management efficiency, it is necessary for us to generate a convenient and intuitive network topology map for our local area network in a timely manner. This network topology map is cleverly used, we can quickly find the source of network faults. Now, I will take "friendly Pinger", a useful network management tool, as an example to describe how to quickly generate a network topology for my local network, the network topology helps i
Palindrome number of the positive and negative sequence is the same number, so we put this number of high-low-level exchange, that is, 1234->4321, and then use the new number to compare with the previous digital exchange is equal, that is, can determine whether this number i
Micro-credit operation is to select a subscription or service number better? This is the tribe on the internet often see some friends are asking questions, in fact, in the tribal view, if there is good content, whether the subscription number or service number, can be done well, There are so many examples in this area. Before the tribe in the media to cash in the
How to solve the micro-letter public number anomaly:
December 16 News, today morning, some netizens reflect, micro-letter public number reading abnormal, point praise and reading number and the actual situation is several times worse.
Take the public number "serious gossip" for example, usually the account headline r
CentOS View System version
cat/etc/redhat-
1) View the version of the CentOS kernel:
[root@localhost ~]# cat /proc/version Linux version 2.6.18-194.el5 (mockbuild@builder10.centos.org) (gcc version 4.1.2 20080704 (Red Hat 4.1.2-48)) #1 SMP Fri Apr 2 14:58:14 EDT 2010
2) Display the system name, the node name, the operating system's release number, the operating system version, the machine ID
Regular expression set for validating numbers
Verification Number: ^[0-9]*$
To verify N-bit numbers: ^\d{n}$
Verify that at least n digits: ^\d{n,}$
Verify the number of m-n bits: ^\d{m,n}$
Verify numbers starting with 0 and non 0: ^ (0|[ 1-9][0-9]*) $
Verify that there is a positive real number with two decimal places: ^[0-9]+ (. [ 0-9]{2})? $
This article is entitled Baidu Quality Department interview questions
2n number, half odd number, half even number, design a program to make the number on the odd digit is odd, the number on the even bit is even, and calculate the space complexity and time complexity of the
Topic:Give 1 positive integers, and find the smallest number in an integer larger than this number in the digit of the same number. For example: 12352874 of the result is 12354278Analysis:The objective of this topic is to find and sort arrays.Of course, the premise is that you have to understand what the idea of this topic looks like. Convert a positive integer t
In Linux, you can view the number of physical CPUs, cores, logical CPUs, and linux. In Linux, when you view the number of physical CPUs, cores, and logical CPUs, we recommend that you enable the number of worker processes to 1 to 4 times the number of CPU cores. So I learned how to view the
The number of decimal places in a repeating prime number must be smaller than that in the prime number itself.
Generally, decimal places with the reciprocal of prime numbers are complex. Because the reciprocal of prime numbers is also a fraction, it must be a round-robin decimal (except for 2 and 5 ), but what is the maximum
Statistics on the number of file lines, number of words, and number of characters in Ruby, and number of ruby lines
In Ruby, we define a wc method to count the number of lines, words, and characters in the file. The ruby code program is as follows:Copy codeThe Code is as fo
The JS Code randomly generates the name, mobile phone number, ID card number, bank card number, and js bank card number.
During development and testing, you often need to enter the name, mobile phone number, ID card number, and ba
public class Computesourceline {public static void main (string[] args) throws FileNotFoundException {//TODO auto-generate D method stub//defines the relevant variable int totalline = 0;int Emptyline = 0;int Commentline = 0;int CodeLine = 0;//We all focus on the scanner class (network search) and The use of the string class (textbook P75 and the Network)//path to the file string strfilename;//using the command line, if there is a command line argument, the file name is obtained from the outside
HTML code:Total number: The interface is as follows:JS Code:Calculate number of input mobile phone number, verify multi-number, filter duplicate number
Question: In the array, subtract the number on the right of the number to get a number pair. Calculate the maximum value of the difference between all number pairs. For example, in the array {2, 4, 1, 16, 7, 5, 11, 9}, the maximum value of the number pair is 11, which is the
GCDTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission (s): 605 Accepted Submission (s): 268
Problem DescriptionThe greatest common divisor GCD (a, B) of two positive integers a and B, sometimes written (a, B), is the largest divisor common to a and B, For example, (1, 2) = 1, (12, 18) = 6.(A, B) can be easily found by the Euclidean algorithm. Now Carp is considering a little more difficult problem:Given integers N and M, how many integer X satisfies
Change the positive number to the corresponding negative number, and change the negative number to the corresponding positive number # include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced."C" Changes the positive number
In software encryption protection technology, a common protection method is license authorization based on hardware fingerprint. This article will introduce the specific hardware fingerprint acquisition technology in detail and provide a demo source code program.
Hardware fingerprint encryption means that after a user obtains and installs the software for free, the software obtains some hardware information (such as the hard disk serial number and BO
#include #include #pragma mark counts the number of characters in each letter entered from the terminal. Use the # sign as the input end flagint main (){int num[26] = {0}, I; char c;while ((c = GetChar ()) = = ' # ') {if (Isupper (c)) {num[c-65]++;}}for (int i = 0; iif (Num[i]) {printf ("%c:%d\n", i+65, Num[i]);}}return 0;}#pragma mark counts the number of words in a line of charactersint main (){Char s[81]
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